What should I bid? (November 2016)


What should I bid? (November 2016)

The best submission for November came from Margaret Foster. She wins a voucher of $30 funded by TBIB, toward any purchase made at the Bridge Shop or Paul Lavings Bridge Books.

I am dealer, West, NS vul.

The bidding:

West North East South
1 Pass  2 Pass
2 Pass 3  Pass
3 Pass 4  All Pass

We play standard. 3=4th suit game forcing.

My partner’s hand was:

He said my bid showed 6 spades and I should bid 3. 5 made at other tables.

What do you think?

Hi Margaret,

I think there is no “right” answer here. Over 3 fourth suit GF, normally it sounds like your bids are:
3NT=54 shape with club stopper
However, there are some problematic hands such as a 5=4=2=2 or a 5=4=1=3 shape with no club stopper – in that case, you will have to do ‘something’! With a 5=4=2=2 shape it is usually better to rebid 3 so that if you could instead rebid 3 or 3, they will be “real” bids showing your extra shape (rather than a “I could still be 54”) – but also, if you can bid 3 ith a 5=4=2=2 shape (with no club stopper), it allows partner to bid 3 or 3 over your 3 to establish the trump suit at a lower-level so then you and partner can diagnose if there’s a potential slam (i.e. imagine if you had to rebid 3 when you have the 5=4=2=2 shape — now partner cannot really set the trump suit to allow cue bidding, and he will have to either bid 4 or 4, or jump to 5 or 5

Having said that, with a very good five-card spade suit (such as your AKJ107), you can in fact treat that as a six-card suit and rebid 3 (which is what I’d definitely do if my shape was 5=4=1=3 with good spades), but with 5=4=2=2 and strong spades, you have a choice between 3 or 3 (my preference is 3). 

However, as to what the actual auction/hands were, I think it’s best for responder to bid 4 over 3 – there’s no need to commit to spades just yet. Bidding 4 just emphasises good diamonds, and if opener has a decent six-card spade suit, opener can still suggest to play in 4 by bidding 4 over 4 (i.e. if opener has a 6=4=2=1 shape, opener would bid 1, then 2, then 3, but then if responder bids 4, opener can now raise to 5).

Hope that helps,

Click here to ask Andy a new question.

Comments are closed.